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Updated on: 17 Oct 2024, 13:29
Originally posted by EgmatQuantExpert on 26 Apr 2018, 05:30.
Last edited by Bunuel on 17 Oct 2024, 13:29, edited 3 times in total.
Last edited by Bunuel on 17 Oct 2024, 13:29, edited 3 times in total.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
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Question Stats:
67% (02:01) correct
33%
(02:20)
wrong
based on 668
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A customer wants to buy a total of 8kg rice of two varieties- A and B. If he can buy each type of rice only in integral multiples of 1 kg then what is the probability that he will buy at least 2 kg rice of each variety?
A. 1/3
B. 4/9
C. 5/9
D. 5/8
E. 2/3
3 deadly mistakes you must avoid in Probability - Exercise Question #2
To solve question 3:Question 3
To read the article: 3 deadly mistakes you must avoid in Probability
A. 1/3
B. 4/9
C. 5/9
D. 5/8
E. 2/3
3 deadly mistakes you must avoid in Probability - Exercise Question #2
To solve question 3:Question 3
To read the article: 3 deadly mistakes you must avoid in Probability
26 Apr 2018, 05:40
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Total no. of cases lie from the range of (8,0) to (0,8) => 9 cases
and no. of favorable ones would be (2,6),(3,5),(4,4),(5,3), and (6,2)
=> probability=5/9
and no. of favorable ones would be (2,6),(3,5),(4,4),(5,3), and (6,2)
=> probability=5/9
General Discussion
Updated on: 29 Apr 2018, 02:35
Originally posted by EgmatQuantExpert on 26 Apr 2018, 05:31.
Last edited by EgmatQuantExpert on 29 Apr 2018, 02:35, edited 1 time in total.
Last edited by EgmatQuantExpert on 29 Apr 2018, 02:35, edited 1 time in total.
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Solution
Given:
• The customer wants to buy 8 kg of rice.
• The rice is of two types- A and B.
• The customer can buy each type of rice only in integral multiples of a kg.
To find:
• The probability such that the customer buys 2kg rice of each variety.
Approach and Working:
We can solve this problem from two methods:
- • By calculating the probabilities of the independent cases
- o 2 kg Rice A and 6 kg rice B
o 3 kg Rice A and 5 kg rice B
o 4 kg Rice A and 4 kg rice B
o 5 kg Rice A and 3 kg rice B
o 6 kg Rice A and 2 kg rice B
- • By non-event method
- o P (customer buys 2kg rice of each variety) = 1- P(customer buys 0 kg rice of one variety)- P(customer buys 1 kg rice of one variety)
Clearly, the 2nd method reduces a lot of calculation.
P(customer buys 0 kg rice of one variety):
- • There are 2 possible ways in which he can buy 0 kg rice of one variety.
- o When he buys 8 kg rice of type A.
o When he buys 8 kg rice of type A.
P(customer buys 1 kg rice of one variety):
- • There are 2 possible ways in which he can buy 1 kg rice of one variety.
- o When he buys 1 kg rice of type A and 1 kg rice of type B.
o When he buys 1 kg rice of type B and 7 kg rice of type B.
Hence, P (customer buys 2kg rice of each variety) = 1- 2/9-2/9= 5/9
Hence, the correct answer is option C.
Answer: C
