Sejal16
Why cant we solve it in format - No of desired / total outcomes ?
The probability of each outcome is not the same. The probability that it will rain is different from the probability that it will not rain.
Take another example: Say what is the probability that you will get an even number on the throw of a die?
There are 6 possible outcomes of a die throw.
Favorable cases = 3 (you get 2/4/6)
Total cases = 6 (you get 1/2/3/4/5/6)
The probability of getting any outcome is the same.
Hence probability = 3/6 = 1/2
Here, the probability of a rainy day is 1/5 and probability of a non-rainy day is 4/5.
Favorable cases are RRNNNNN, RNRNNNN, NRNRNNN ... etc
All cases are NNNNNNN, RNNNNNN, NRNNNNN, ... etc
Probability of each outcome is not the same since the probabilities of R and N are not the same.
Probability of getting RRNNNNN = (2/10)*(2/10)*(8/10)*(8/10)*(8/10)*(8/10)*(8/10) = 2^{17} / 10^7
Probability of getting RNRNNNN = 2^{17} / 10^7
There will be 7!/2!*5! = 21 such arrangements
Hence total probability = 21 * 2^{17} / 10^7
Answer (D)