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Does anyone know a shortcut to derive at "4" using the prime factorization? Or do we actually have to write down all the factors and just do the prime factorization to double-check that we have found all possible factors?
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Method i used to drive at the correct answer is following

prime Factorization of 42 = 2^1 * 3^1 * 7^1

Now any factor of 42 will be divisible by 3 when it has 3 as its prime factor , means any factor of 42, should have power of 3 as 1 and 2 and 7 can have power as 0,1

3^1 * 2^0 * 7^0 (only 1 power of 3 and 0 zero power of 2 and 7 )= 3
3^1 * 2^1 * 7^0 (only 1 power of 3 and 2 zero power of 7 ) = 6
3^1 * 2^0 * 7^1 (only 1 power of 3 and 7 zero power of 2 ) =21
3^1 * 2^1 * 7^1 (all have 1 power each ) = 42
Correct Choice option is C
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Bunuel
How many of the factors of 42 are divisible by 3 ?

A. 2
B. 3
C. 4
D. 6
E. 8

42=2*3*7
Total# factors: 2*2*2
#Factors where the power of 3 is 1: 2*1*2= 4
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Bunuel
How many of the factors of 42 are divisible by 3 ?

A. 2
B. 3
C. 4
D. 6
E. 8

42 = 3 x 2 x 7

Thus, 3, 3 x 2, 3 x 7, and 3 x 2 x 7, are all divisible by 3.

Answer: C
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julie123
Does anyone know a shortcut to derive at "4" using the prime factorization? Or do we actually have to write down all the factors and just do the prime factorization to double-check that we have found all possible factors?


Prime factorization of 42 is 2*3*7.
total number of factors = 2*2*2 = 8

total number of factors which are not divisible by 3 is calculated by finding factors of 2*7 which is 4.
no. of factors divisible by 3 = total - no. of factors not divisible by 3
= 8-4
= 4
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soapbolt
Method i used to drive at the correct answer is following

prime Factorization of 42 = 2^1 * 3^1 * 7^1

Now any factor of 42 will be divisible by 3 when it has 3 as its prime factor , means any factor of 42, should have power of 3 as 1 and 2 and 7 can have power as 0,1

3^1 * 2^0 * 7^0 (only 1 power of 3 and 0 zero power of 2 and 7 )= 3
3^1 * 2^1 * 7^0 (only 1 power of 3 and 2 zero power of 7 ) = 6
3^1 * 2^0 * 7^1 (only 1 power of 3 and 7 zero power of 2 ) =21
3^1 * 2^1 * 7^1 (all have 1 power each ) = 42
Correct Choice option is C
 
­thank for you method­
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Bunuel
How many of the factors of 42 are divisible by 3 ?

A. 2
B. 3
C. 4
D. 6
E. 8
\(­42 = 2*3*7\)

For the number to be divisible by 3 we must have the factors as 3 , 6 , 21 & 42, Answer must be (C) 4
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