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18 Jan 2019, 05:12
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:32) correct
25%
(01:59)
wrong
based on 208
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Not Attempted Yet
[Math Revolution GMAT math practice question]
32 teams compete in the World Cup of Soccer. They are divided into eight groups of four teams (groups A to H) to compete in the ‘group stage’. Teams in each group play one another in a round-robin competition, with the top two teams of each group advancing to the knockout stage. What is the total number of matches played at the group stage?
A. 24
B. 36
C. 48
D. 56
E. 64
32 teams compete in the World Cup of Soccer. They are divided into eight groups of four teams (groups A to H) to compete in the ‘group stage’. Teams in each group play one another in a round-robin competition, with the top two teams of each group advancing to the knockout stage. What is the total number of matches played at the group stage?
A. 24
B. 36
C. 48
D. 56
E. 64
Archit3110
Major Poster
18 Jan 2019, 05:41
Kudos
Bookmarks
MathRevolution
total matches one team plays in each group : 4c2 = 6
total groups = 8
total group matches : 8 * 6 = 48 IMO C
18 Jan 2019, 07:44
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Archit3110
I arrived at C as well, but am confused by your combination. How would the number of matches a team plays in each group =6 and why would the combo = 4c2?
e.g.
Group A Pairings: (1 v 2, 1 v 3, 1 v 4), (2 v 1, 2 v 3, 2 v 4), (3 v 1, 3 v 2, 3 v 4) (4 v 1, 4 v 2, 4 v 3) and then subtract redundant combinations... leaving you with (1 v 2, 1 v 3, 1 v 4), (2 v 3, 2 v 4) and (3 v 4)
6 unique matches in each group * 8 groups =48
Thanks in advance for your help!
