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If j and k are positive integers, is 6 a factor of j?
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aragonn
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If j and k are positive integers, is 6 a factor of j? [#permalink] New post  27 Mar 2019, 23:14
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39% (01:07) correct 61% (00:53) wrong based on 98 sessions

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If j and k are positive integers, is 6 a factor of j?

(1) 6 is a factor of jk.

(2) 6 is not a factor of k.
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LevanKhukhunashvili
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If j and k are positive integers, is 6 a factor of j? [#permalink] New post  Updated on: 28 Mar 2019, 02:22
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Learn from my mistakes: Try to catch why below reasoning is incorrect

1 stm - if j=6 k=6 the answer is yes. but if j=1 k=6 the answer is no - not suff
2 stm - nothing about j - not suff

1-2 stm together, if jk is divisible by 6 and k is not, then j must be divisible by 6 suff

IMO
Ans: C

Originally posted by LevanKhukhunashvili on 28 Mar 2019, 00:30.
Last edited by LevanKhukhunashvili on 28 Mar 2019, 02:22, edited 3 times in total.
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aragonn
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Re: If j and k are positive integers, is 6 a factor of j? [#permalink] New post  28 Mar 2019, 01:58
LevanKhukhunashvili - Have you considered the case of j=2,k=3 ?
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LevanKhukhunashvili
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Re: If j and k are positive integers, is 6 a factor of j? [#permalink] New post  28 Mar 2019, 02:13
aragonn Ouch :) :(
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Re: If j and k are positive integers, is 6 a factor of j? [#permalink] New post  15 Sep 2020, 09:59
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aragonn wrote:
If j and k are positive integers, is 6 a factor of j?

(1) 6 is a factor of jk.

(2) 6 is not a factor of k.


Both statements are satisfied by j=6 and k=1.
In this case, the answer to the question stem is YES.
Both statements are satisfied by j=3 and k=2.
In this case, the answer to the question stem is NO.
Since the answer is YES in the first case but NO in the second case, the two statements combined are INSUFFICIENT.

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