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16 Apr 2019, 21:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (02:09) correct
19%
(02:37)
wrong
based on 230
sessions
History
Date
Time
Result
Not Attempted Yet
In how many ways can a committee of 5 members be formed from 4 women and 6 men such that at least 1 woman is a member of the committee?
(A) 112
(B) 156
(C) 208
(D) 246
(E) 252
(A) 112
(B) 156
(C) 208
(D) 246
(E) 252
eswarchethu135
GMAT 2: 640 Q49 V27
Posts: 276
16 Apr 2019, 22:18
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Total number of ways of selecting 5 members from 10 members are \(^{10}C_5\) ways.
Number of ways of selecting a team such that there is no women in the team are \(^6C_5\) ways.
Number of ways of selecting a committee such that at least 1 woman is a member of the committee are \(^{10}C_5\) - \(^6C_5\)
= 252 - 6
= 246
OPTION: D
Number of ways of selecting a team such that there is no women in the team are \(^6C_5\) ways.
Number of ways of selecting a committee such that at least 1 woman is a member of the committee are \(^{10}C_5\) - \(^6C_5\)
= 252 - 6
= 246
OPTION: D
General Discussion
Archit3110
16 Apr 2019, 22:44
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Bunuel
make cases and solve
total 5 members to be choosen
so
we can have
6c4 * 4c1=60
6c3*4c2=120
6c2*4c3=60
6c1*4c4=6
total 246
IMO D
