ScottTargetTestPrep
I) \(a < b\)
II) The distinct prime factors of \(a^{2}\) are also factors of \(b\).
III) \(0<\frac{a}{b}\leq{1}\)
A) None
B) II only
C) III only
D) I and II only
E) II and III only
Although a is a factor of b, a could equal b. So I is not true.
However, since the distinct prime factors of a^2 are also distinct prime factors of a, then they are also factors of b. So II is true.
If a is negative and b is positive, then a/b is negative. So III is not true.
Answer: B[/quote]
Hi, isn't factorial of negative number supposed to be undefined?[/quote]
Yes, you’re right that the factorial of a negative number is undefined; however, this question does not involve any discussion about factorials. You might be confusing the term “factor” with “factorial,” which are very different things. A factor of an integer is another integer that divides the first integer without any remainder. For example, 2 and 3 are factors of 6, but 5 is not. Factorial, which is denoted by the exclamation mark (!), is the product of all the positive integers less than or equal to a given positive integer. For instance, 3! = 3 x 2 x 1, 5! = 5 x 4 x 3 x 2 x 1, etc.[/quote]
ScottTargetTestPrepSO I understand the answer but need clarification. Should we always think of the possible negative factors? Or why would we in this case?
Because say if I’m asked for the factors of 6, i say it has 4 factors (only the +ve), either as a question or as an intermediary step in a question. There are many questions that test this logic without accounting for -ve factors
I’m really asking - what cue should we have to separate the 2 cases?
Is it bc a and b integers themselves can be + or -? So if the question starts by stating a and b are +ve integers - then we ignore the -be factors (like -3 as a factor of 6)
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