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Bunuel
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Based on the chart above, which of the following statements must be tr 03 Jun 2019, 01:51
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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55% (hard)

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69% (02:14) correct 31% (02:31) wrong based on 376 sessions

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Based on the chart above, which of the following statements must be true?

I. A cocktail made with one part Fine and Dandy and two parts Monster Smash (and no other ingredients) will be more than 9% alcohol.
II. A cocktail made with 11.5 grams each of all three liquors (and no other ingredients) will be more than 7% alcohol.
III. A cocktail made with one part Delicate Flower, two parts Fine and Dandy, and one part alcohol-free mixer (and no other ingredients) will be more than 7% alcohol.


(A) I
(B) II
(C) III
(D) I and II
(E) I and III


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D
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Lampard42
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Based on the chart above, which of the following statements must be tr 03 Jun 2019, 02:59
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Statement I - 1/3*6% +2/3*12% = 10% - true
Statement II - 1/3*4%+ 1/3*6% +1/3*12% = 7.33%- true
Statement III - 1/4*4%+2/4*6%+1/4*0% = 4.33% - false

So option D - I and II
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Based on the chart above, which of the following statements must be tr 07 Mar 2022, 07:01
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I. 0.06x + 0.12*2x > 0.09*3x
6x + 24x > 27x
30x > 27x (True)

II. 0.04*11.5 + 0.06*11.5 + 0.12*11.5 > 0.07*3*11.5
46+69+138 > 241.5
253 > 241.5 (True)

III. 0.04x + 0.06*2x + 0.12x > 0.07*4x
4x + 12x + 12x > 28x
28x > 28x (False)

Therefore, our answer is (D)

Bunuel I know this is not the best way to solve this question but is the approach correct?
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Based on the chart above, which of the following statements must be tr 30 Nov 2024, 05:09
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I. A cocktail made with one part Fine and Dandy and two parts Monster Smash (and no other ingredients) will be more than 9% alcohol.
--> Use alligation, 12-x/x-6= 1/2 hence, x=10%>9% Hence, I is true.

II. A cocktail made with 11.5 grams each of all three liquors (and no other ingredients) will be more than 7% alcohol.
--> (4%+6%+12%) of 11.5 grams = x% of 3*11.5
22= 3x
x>7%. Hence, II is true.

III. A cocktail made with one-part Delicate Flower, two parts Fine and Dandy, and one-part alcohol-free mixer (and no other ingredients) will be more than 7% alcohol.

Just to check, can use average distribution or alligation

1 part of 4%, 2 parts 6%, 1 part 12%.
Hence, average is 7%. Hence, III is incorrect.

Therefore, Option D.
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Based on the chart above, which of the following statements must be tr 05 Jan 2025, 14:45
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statement 3 will yield 4% of alcohol and not 4.33%. Though it doesn't change the answer.
Lampard42
Statement I - 1/3*6% +2/3*12% = 10% - true
Statement II - 1/3*4%+ 1/3*6% +1/3*12% = 7.33%- true
Statement III - 1/4*4%+2/4*6%+1/4*0% = 4.33% - false

So option D - I and II
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Based on the chart above, which of the following statements must be tr 05 Jan 2025, 15:11
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Fastest way is to calculate weighted averages:

I) (1*6 + 2*12)/3 = 30/3 = 10% > 9% [TRUE]

II) (4 + 6 + 12)/3 = 22/3% > 21/3% (so we know it’s >7% without having to even do more math) [TRUE]

III) technically we don’t have to do, since we know I & II are right, but if we were to:
(4 + 2*6 + 0)/4 = 16/4 = 4% < 7% [FALSE]
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Based on the chart above, which of the following statements must be tr 13 Mar 2026, 03:46
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Bunuel

Based on the chart above, which of the following statements must be true?

I. A cocktail made with one part Fine and Dandy and two parts Monster Smash (and no other ingredients) will be more than 9% alcohol.
II. A cocktail made with 11.5 grams each of all three liquors (and no other ingredients) will be more than 7% alcohol.
III. A cocktail made with one part Delicate Flower, two parts Fine and Dandy, and one part alcohol-free mixer (and no other ingredients) will be more than 7% alcohol.


(A) I
(B) II
(C) III
(D) I and II
(E) I and III


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Use theory of WA and minimize the actual calculations.

I. A cocktail made with one part Fine and Dandy (6%) and two parts Monster Smash (12%) will be more than 9% alcohol.

Had they been taken in equal quantities, the overall alcohol concentration would have been 9%. but since Moster Smash is more, average will be closer to 12 and hence higher than 9%.
True.


II. A cocktail made with 11.5 grams each of all three liquors (and no other ingredients) will be more than 7% alcohol.

$4%, 6% and 12% in equal quantities.

One part 4% and one part 12% will average out to two parts 8%. Then one part 6% is added.
If equal parts of 8% and 6% were added, then average would be 7%. But since more parts of 8% are added, actual avg will be more than 7%
True.


III. A cocktail made with one part Delicate Flower (4%) , two parts Fine and Dandy (6%), and one part alcohol-free mixer (0% alcohol will be more than 7% alcohol.

Any mix of 4%, 6% and 0% alcohol cannot give 7% alcohol.
So not true.

Answer (D)

Weighted Avg and Mixtures Basics:
https://anaprep.com/arithmetic-weighted-averages/
https://anaprep.com/arithmetic-mixtures/
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