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Bunuel
A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 16/25. How many marbles are in the bag?

A. 24
B. 48
C. 60
D. 72
E. 84

Let total marbles be N; So probability of neither marble being Red is [(n-12)/n]*[(n-12)/n]=16/25 as they are replaced after picking.

So sub answer choices to arrive at the answer; Option C (48/60)*(48/60)=16/25
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Bunuel
A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 16/25. How many marbles are in the bag?

A. 24
B. 48
C. 60
D. 72
E. 84

total red = 12
and not red = x
so total marbles = 12+x
now given P of not red two marbles ;
(x/12+x)^2 = 16/25
x/x+12 = 4/5
solve for x = 48
so total 48+12 = 60
IMO C
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Bunuel
A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 16/25. How many marbles are in the bag?

A. 24
B. 48
C. 60
D. 72
E. 84

Replace the first marble with what? What if it is replaced with a red marble? I guess the wording is wrong. Bunuel

Posted from my mobile device
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Bunuel
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tyildirim92
Bunuel
A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 16/25. How many marbles are in the bag?

A. 24
B. 48
C. 60
D. 72
E. 84

Replace the first marble with what? What if it is replaced with a red marble? I guess the wording is wrong. Bunuel

Posted from my mobile device

Yes, the wording is not perfect but what the question means that the first marble after it was picked is put back.
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Let n be the total number of marbles

((n-12)/n)^2= 16/25

(n-12)/n=4/5

5n-60 = 4n

n= 60

C.

Hope it helps
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