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23 Jun 2019, 07:17
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (02:41) correct
19%
(02:56)
wrong
based on 743
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Machine A, working alone at a constant rate, can complete a certain production lot in x hours. Machine B, working alone at a constant rate, can complete 1/5 of the same production lot in y hours. Machines A and B, working together, can complete 1/2 of the same production lot in z hours. What is the value of y in terms of x and z?
A. (5x - 10z)/ 2xz
B (2xz) / (5x - 10z)
C. (5xz)/ (x + z)
D. xz/ x + z
E. xz/ x + 2z
A. (5x - 10z)/ 2xz
B (2xz) / (5x - 10z)
C. (5xz)/ (x + z)
D. xz/ x + z
E. xz/ x + 2z
23 Jun 2019, 07:36
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Let their rates be R
R(a) =1/x , R(b) =1/5y
R(a)+ R(b) = 1/2z
1/x + 1/5y = 1/2z
(5y+ x)/(5xy) =1/2z
5xy = 2z(5y+x)
5xy - 10yz = 2xz
y(5x - 10z) = 2xz
y = 2xz/(5x - 10z)
Answer B
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R(a) =1/x , R(b) =1/5y
R(a)+ R(b) = 1/2z
1/x + 1/5y = 1/2z
(5y+ x)/(5xy) =1/2z
5xy = 2z(5y+x)
5xy - 10yz = 2xz
y(5x - 10z) = 2xz
y = 2xz/(5x - 10z)
Answer B
Posted from my mobile device
General Discussion
23 Jun 2019, 07:43
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gmat1393
work = rate * time
let rate of A be R1
rate of B be R2
W be the work
machine A work
W = R1*x
R1 = \(\frac{W}{x}\)
machine B work
\(\frac{W}{5}\) = R2*y
R2 = \(\frac{W}{5y}\)
both machine working together
\(\frac{W}{2}\) = (R1+R2)*z
\(\frac{W}{2}\) =(\(\frac{W}{x}\)+\(\frac{W}{5y}\))* z
\(\frac{1}{2z}\)-\(\frac{1}{x}\) = 1/5y
\(\frac{5(x-2z)}{2xz}\) = \(\frac{1}{y}\)
y = \(\frac{2xz}{5x-10z}\)
B is the answer
