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Maximum number of that he can mix= 2/3+1/3+1=2 cups

Bunuel
A salad dressing requires oil, vinegar, and water in the ratio 2 : 1 : 3. If Oliver has 1 cup of oil, 1/3 cup of vinegar, and 2 cups of water, what is the maximum number of cups of dressing that he can mix?

A. 1
B. 2
C. 3
D. 4
E. 5
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Bunuel
A salad dressing requires oil, vinegar, and water in the ratio 2 : 1 : 3. If Oliver has 1 cup of oil, 1/3 cup of vinegar, and 2 cups of water, what is the maximum number of cups of dressing that he can mix?

A. 1
B. 2
C. 3
D. 4
E. 5

total ratio sum ; 6
so vinegar is least ; 1/3*6 ; 2 cups possible
IMO B
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Oil:Vinegar:Water = 2:1:3

Maximum oil = 1 cup
Therefore, convert the oil proportion to 1 by dividing the ratio by 2.
So, oil:vinegar:water = 1:1/2:3/2 ......(i)
Then, maximum vinegar= 1/3 cup
Therefore, convert vinegar proportion of (i) to 1/3 by multiplying the ratio of (i) by 2/3;
So, transformed oil:vinegar:water=2/3:1/3:1

Maximum number of cups = 2/3 + 1/3 + 1
=2 cups

So, the answer is B in my opinion.
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Overall # of items required for topping is 7. 2/7, 1/7 and 3/7 of oil, vinegar and water respectively required.
We have 1 cup 1/3 cup and 2 cups of the required elements. In order to understand our capabilities we should have common
denominators.

7 and 3 have the least common multiplier of 21.

21/ 21, 7/21 and 42/ 21 of present components. Required are 6/ 21 (retrieved through multiplying both nominator and denominator by 3) 3/ 21 and 9/21. After making 2 toppings we will have only 1/21 cup of vinegar so despite the presence of the other components we will be short for one instrumental one, hence only 2 toppings will be able to create.

Answer B
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