A computer can perform 1,000,000 calculations per second. At this rate

Question

A computer can perform 1,000,000 calculations per second. At this rate, how many hours will it take this computer to perform the 3.6*10^11 calculations required to solve a certain problem?

A. 60
B. 100
C. 600
D. 1,000
E. 6,000

PS83502.01

helg · Accepted Answer

B) 100
1000000 is 10^6, therefore we have the speed of 10^6 per second or 3600x10^6 = 3.6x10^9 per hour. Now, we need to make 10^2 or 100 times more calculations, therefore it will take 100 hours.

Professor · Answer

B. (3.6 x 10^11)/10^6 = 36 x 10^4 seconds = 100 hours

haas_mba07 · Answer

B) 100

(3.6 x 10^11)/(60x60x10^6)
= 10^4/100 = 100 hours

necromonger · Answer

36*10^10/10^6 = 36*10^4/(36*10^2) = 100 hours

sgrover · Answer

(B)

total time in secs = 3.6 * 10^11/10^6 = 3.6 * 10^5 secs
= 3.6 * 10^5/3600 hrs = 100 hrs

zonk · Answer

B

1 x 10^6 calc/sec = 1 x 10^6 calc/sec * 60 sec/min * 60 min/hr = 1 x 10^6 calc/sec * 3600 sec/hr = 1 x 10^6 calc/sec * 3.6 x 10^3 sec/hr = 3.6 x 10^9 calc/hr

3.6 x 10^11 calc / 3.6 x 10^9 calc/hr = 10^2 hr = 100 hr

x2suresh · Answer

(3.6 x 10^11 )/ (10^5) = 3.6 * 10 ^5 sec
 = (3600 * 10^2 ) /3600 hrs
 = 100 hrs

B

kp1811 · Answer

b. 100
per hour the computer performs  3600 X 10^6  calculations which is =  3.6 X 10^9 
So time taken to perform  3.6 X 10^11  calculations =  3.6 X 10^11 / 3.6 X 10^9  = 100hrs

tjerkrintjema · Answer

I would say answer B
Because the computer can calculate 1,000,000 calculations per second OR 3600,000,000 (3600*1,000,000) per hour, which is similar to 3.6*10^9.
The question states a problem of the magnitude 3.6^11

11-9 = 2, therefore 10^2 = 100

OptimusPrepJanielle · Answer

A computer can perform 1,000,000 calculations per second. At this rate, how many hours will it take this computer to perform the 3.6*10^11 calculations required to solve a certain problem?

A. 60
 B. 100 
C. 600
D. 1,000
E. 6,000

Always read carefully. It could be easy to read quickly and miss that the rate is given in seconds but the answer choices are given in hours. The first step is to convert the rate into hours. This will make the calculations easier.
1000000 calculations = 1 x 10^6 calculations
The rate is 3.6 x 10^9 calculations per hour.
3.6 * 10^9 calculations per hour= 3.6 * 10^11 calculations per x hours
(3.6 *10^9 calculations per hour) ÷ (3.6 * 10^11 calculations) = x hours
x hours =  10^2 = 100

law258 · Answer

100.

Here's the calculation you should have derived:

(3.6 x 10^11 calc) x (1sec/10^6) x (1min/60sec) x (1hr/60min)

sam7 · Answer

Computer can perform = 10^6 calculations /sec
So for 3.6 x 10^11 calculations it will require 360000 seconds for computing.

i.e., 360000 seconds = 360000/ (60 x 60) hours = 100 hours.

TheNightKing · Answer

1 million (6 zeros) per second.

We need to perform 3.6*(10^11). Which is 36*10^10. Let's take out the million (6 zeros so we are left with 4 zeros) 36,0000 Millions

We need number of hours so let's divide by 3600. (60minutes*60seconds)

360000/3600=100

Hence B.

Note: Just play with zeros carefully that's it

ScottTargetTestPrep · Answer

We note that 1,000,000 = 10^6. Thus, the number of seconds it takes to perform 3.6*10^11 calculations is:

(3.6*10^11 / 10^6) = 3.6 x 10^5

Since 1 hour = 3600 seconds, the number of hours is:

3.6 x 10^5 / 3.6 x 10^3 = = 10^2 = 100

Answer: B

RAHUL_GMAT · Answer

We just need to divide the total time by cal per sec

3.6 * 10 ^ 11 / 10 ^ 6 = 3.6 * 10 ^5 = 360000 sec

Now 1 hr = 3600 sec

so 
360000 sec = 360000/ 3600 hrs = 100 hrs

Basshead · Answer

A computer can perform 1,000,000 calculations per second. At this rate, how many hours will it take this computer to perform the 3.6*10^11 calculations required to solve a certain problem?

My approach:

A computer can perform  10^6  calculations per second. How many hours will it take to perform  3.6*10^11 ?

\frac{3.6 *10^{11} }{ 10^6} = 3.6 * 10^5  seconds

\frac{360000 }{ 3600} = 100 hours

Answer is B

bumpbot · Answer

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A computer can perform 1,000,000 calculations per second. At this rate

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