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jackfr2
a certain bag contains 6 marbles of which 4 are red and 2 are white in color. if babu is to pick out two marbles from the bag simultaneously & at random, what is the probability that one is red & other one is white?
a. 1/5
b. 1/3
c. 1/15
d. 8/15
e. 4/9

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Red & blue = 2c1 * 4/6 * 2/5 = 8/15
IMO D
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a certain bag contains 6 marbles of which 4 are red and 2 are white in color. if babu is to pick out two marbles from the bag simultaneously & at random, what is the probability that one is red & other one is white?
Sol=> The probability to select the marbles such that one is red and one is white is (4/6)*(2/5) But the order can be any one first red then white or first white then red so they can be arranged in 2! ways so the answer will be (4/6)*(2/5)*2! = 8/15
Hence option D
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jackfr2
a certain bag contains 6 marbles of which 4 are red and 2 are white in color. if babu is to pick out two marbles from the bag simultaneously & at random, what is the probability that one is red & other one is white?
a. 1/5
b. 1/3
c. 1/15
d. 8/15
e. 4/9

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\(\frac{4C_1*2C_1}{6C_2}=\frac{4*2}{15}=\frac{8}{15}\), Answer will be (D)
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