The Quasi JX is a new car model. Under ideal driving conditions, the Q

Question

The Quasi JX is a new car model. Under ideal driving conditions, the Quasi Jx’s fuel economy is E kilometers per liter (E  \frac{km}{L} ) when its driving speed is constant at S kilometers per hour (S  \frac{km}{h} ).

In terms of the variables S and E, select the expression that represents the number of liters of fuel used in 1 hour of driving under ideal driving conditions at a constant speed S, and select the expression that represents the number of liters of fuel used in a 60 km drive under ideal driving conditions at a constant speed S. Make only two selections, one in each column.

Rishabh121 · Accepted Answer

fuel efficiency or mileage is basically: distance traveled / no. of liters. (km/L)
Hence, No. of liters = Distance traveled / fuel efficiency (mileage)

Liters of fuel consumed in 1 hour = speed * 1 / mileage = S / E
Liters of fuel consumed in 60 km = Distance / mileage = 60 / E

GMATCoachBen · Answer

Video solution here (3:15):

https://www.youtube.com/watch?v=EF5m3yy2NqU

Apt0810 · Answer

S/E - represents litres of fuel in 1 hour

E is the economy in km for per litre, so for 1 km it would 1/E litre, so for 60 km - 60/E litres

Posted from my mobile device

Sajjad1994 · Answer

Official Explanation

Strategize:  Choose from the available options the expression that yields the intended value.

RO1, Liters of fuel in 1 hr: Strategize

The Quasi JX travels E kilometers per liter of fuel  (E\frac{km}{L})  at S kilometers per hour  (S\frac{km}{hr}) . Therefore the Quasi JX requires  \frac{1}{E}  liters of fuel to travel 1 km. Since the Quasi JX travels S kilometers per hour, it requires  \frac{1}{E}   \frac{L}{km}  × S  \frac{km}{hr} , or  \frac{S}{E} \frac{L}{hr}

The correct answer is A,  \frac{S}{E} .

RO2, Liters of fuel in 60 km: Strategize

The Quasi JX travels E kilometers per liter of fuel  (E\frac{km}{L}) . Therefore the Quasi JX requires  \frac{1}{E}  liters of fuel to travel 1 km. Given this, the Quasi JX uses 1/E L/km × 60 km, or 60/E L of fuel to travel 60 km.

The correct answer is C,  \frac{60}{E}

kayarat600 · Answer

Is therexa more reasonable way to solve this.

cheshire · Answer

the most helpful reply is the simplest way of explaining it and the easiest way to solve it.

Usernamevisible · Answer

Whenever you're confused about whether to multiply or divide, don't ask "Do I multiply or divide?" Instead, ask "What unit do I want, and what unit do I have?" The units will force the operation. If you have km/liter and want liters, divide by km/liter: Fuel = Distance ÷ (km per liter). For example, if a car gives 20 km/liter, then traveling 100 km uses 100 ÷ 20 = 5 liters, not 2000 liters. Similarly, if speed is 80 km/h and mileage is 20 km/liter, then in 1 hour the car travels 80 km and uses 80 ÷ 20 = 4 liters, so Fuel in 1 hour = Speed ÷ Mileage = S/E.

A useful rule is: to get the numerator unit, multiply; to get the denominator unit, divide. Also do a quick reality check—if your calculation gives an absurdly large or small number, you've probably used the wrong operation.

A useful rule is: to get the numerator unit, multiply; to get the denominator unit, divide. Also do a quick reality check—if your calculation gives an absurdly large or small number, you've probably used the wrong operation.

Liters of fuel in 1 hour	Liters of fuel in 60 km
		S/E
		E/S
		60/E
		60/S
		S/60
		E/60

The Quasi JX is a new car model. Under ideal driving conditions, the Q

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The Quasi JX is a new car model. Under ideal driving conditions, the Q

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

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My Rewards