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26 Dec 2019, 02:27
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
68% (02:38) correct
33%
(02:34)
wrong
based on 440
sessions
History
Date
Time
Result
Not Attempted Yet
If 3A = 4B = 5C = 6D and A + B + C + D = 1026, find the values of A, B, C and D.
A. 171, 228, 285, 342
B. 342, 285, 228, 171
C. 180, 216, 270, 360
D. 360, 270, 216, 180
E. None of these
A. 171, 228, 285, 342
B. 342, 285, 228, 171
C. 180, 216, 270, 360
D. 360, 270, 216, 180
E. None of these
globaldesi
Joined: 28 Jul 2016
Last visit: 23 Feb 2026
Posts: 1,141
Given Kudos: 67
Location: India
Concentration: Finance, Human Resources
Schools: ISB '18 (D)
GPA: 3.97
WE:Project Management (Finance: Investment Banking)
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26 Dec 2019, 09:53
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If 3A = 4B = 5C = 6D and A + B + C + D = 1026, find the values of A, B, C and D.
Let 3A = 4B = 5C = 6D = K
so \(A =\frac{ K}{3}\)
\(B=\frac{ K}{4}\)
\(C= \frac{K}{5}\)
\(D=\frac{ K}{6}\)
NOW GIVEN
A + B + C + D = 1026
THUS
\(\frac{ K}{3} +\frac{ K}{4}+ \frac{ K}{5}+\frac{ K}{6} = 1026\)
OR
\(\frac{57K}{60 }= 1026\)
Solve for K
where K = 1080
substitute back for each value
\(A =\frac{ 1080}{3} = 360\)
\(B=\frac{ 1080}{4} = 270\)
\(C= \frac{1080}{5} = 216\)
\(D=\frac{ 1080}{6}= 180\)
D matches all these and thus the answer
Let 3A = 4B = 5C = 6D = K
so \(A =\frac{ K}{3}\)
\(B=\frac{ K}{4}\)
\(C= \frac{K}{5}\)
\(D=\frac{ K}{6}\)
NOW GIVEN
A + B + C + D = 1026
THUS
\(\frac{ K}{3} +\frac{ K}{4}+ \frac{ K}{5}+\frac{ K}{6} = 1026\)
OR
\(\frac{57K}{60 }= 1026\)
Solve for K
where K = 1080
substitute back for each value
\(A =\frac{ 1080}{3} = 360\)
\(B=\frac{ 1080}{4} = 270\)
\(C= \frac{1080}{5} = 216\)
\(D=\frac{ 1080}{6}= 180\)
D matches all these and thus the answer
General Discussion
27 Dec 2019, 08:18
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I plugged in answer choices for this question.
I started with option C, just because.
From answer choice C, its given A= 180. Therefore, 3A = 3(180) = 540
From the equation given, 3A= 4B, therefore 4B = 540. Then B =540/4 = 135 ---> this is not the same value as what is given for option C for value B i.e. 180, 216, 270, 360
I stopped progressing with option C.
Then I moved on to choice D.
It's given A= 360, therefore 3A = 3 (360) =1080
From the equation given, 3A= 4B, therefore 4B = 1080. Then B = 270 ---> this is the same value as what is given for option D for value B i.e. 360, 270, 216, 180
I stop calculating and hit D as my answer.
I started with option C, just because.
From answer choice C, its given A= 180. Therefore, 3A = 3(180) = 540
From the equation given, 3A= 4B, therefore 4B = 540. Then B =540/4 = 135 ---> this is not the same value as what is given for option C for value B i.e. 180, 216, 270, 360
I stopped progressing with option C.
Then I moved on to choice D.
It's given A= 360, therefore 3A = 3 (360) =1080
From the equation given, 3A= 4B, therefore 4B = 1080. Then B = 270 ---> this is the same value as what is given for option D for value B i.e. 360, 270, 216, 180
I stop calculating and hit D as my answer.
