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03 Jan 2020, 02:13
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Difficulty:
75%
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Question Stats:
55% (02:19) correct
45%
(02:21)
wrong
based on 189
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In a foggy night, the visibility is limited to just 300 mts. Exactly 2 minutes after the driver of a speeding car could see a bus ahead, the driver of the bus sees the car vanishing from his sight, ahead. If the speed of the bus is 36 kmph, what is the speed of the car?
A. 54 kmph
B. 45 kmph
C. 42 kmph
D. 40 kmph
E. 38 kmph
A. 54 kmph
B. 45 kmph
C. 42 kmph
D. 40 kmph
E. 38 kmph
Car driver sees bus at 300 m away for the first time and then bus sees car vanishing 300m away so total relative distance travelled is 600 m
Total time taken =2 min
Relative speed of car with respect to bus = 600/2 mtr per min= 18kmph
Speed of car = speed of bus + relative speed of car wrt bus
36 kmph +18 kmph
54 kmph
Answer A
Total time taken =2 min
Relative speed of car with respect to bus = 600/2 mtr per min= 18kmph
Speed of car = speed of bus + relative speed of car wrt bus
36 kmph +18 kmph
54 kmph
Answer A
General Discussion
