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Bunuel
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I used the options:

Difference between the times must be 12 minutes.

Starting always with C.

C) 3km/5kmph = 36 min 1/2 = 30 min --- Discard

D) 2km/5kmph = 24 min 1/3 = 20 min --- Discard

E) 6km/5kmph = 72 min 6/6 = 60 min --- Correct one

E
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Bunuel
If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the departure of the train. Find the distance to the station.

A. 2 km
B. 3 km
C. 4 km
D. 5 km
E. 6 km

We know, \(D=\frac{Δt×S1×S2}{S1–S2}\)

So, \(D=\frac{12×5×6}{60×1}\)
=6 km
Answer is E

Posted from my mobile device
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60 mins ------------- 5 km
1 min ---------------- 5/60 = 1/12 km/min

60 mins ------------- 6 kms
1 min --------------- 6/60 = 1/10 km/min

speed x time = distance

(t+7)/12 = d

(t-5)/10 = d

(t+7)/12 = (t-7)/10

t=65 mins

d = (t+7)/12 = 72/12 = 6 kms (E)
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IMO E


\(­d = t*s\)


below, x is the distance av. time needed to reach the station

(1)  \(d = 5 ( x + \frac{7}{60} ) \)                      
(First person walks at a speed of 5 kmph , and arrives 7 minutes late, which is 7/60 hours)

(2)  \(d = 6 ( x - \frac{5}{60} )     \)                   (Second person walks at a speed of 6kmph , and arrives 5 minutes early , which is 5/60 hours) 



(1) = (2)

\(5x + \frac{7}{12} = 6x - \frac{5}{10}\\
\\
x = \frac{65}{60} \)



Replace \(x=\frac{65}{60}\) in (1) or (2) and get d = 6 mins which is option E 
 ­This was my solution, hope you liked it.
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Bunuel
Can we solve it like this?

5*(t+7/60) = 6*(t-10/60)?
As I use this every time for such questions but in this particular question I am getting 7 kms and not the required 6 kms
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Bunuel
Can we solve it like this?

5*(t+7/60) = 6*(t-10/60)?
As I use this every time for such questions but in this particular question I am getting 7 kms and not the required 6 kms
You have taken 10 instead of 5.
5*(t+7/60)= 6*(t-10/60)

You can also find the time in minutes and convert to hour later if required.
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