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I did it using a different method:

20%. 30%
\ /
24%
/ \
6 : 4
Therefore cost of pen=3/5 of original cost 15 ie 9 - option E

Posted from my mobile device
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Cheaper(Pen) = 20% and Dearer(Pencil) = 30%.

Overall: 24%

Rule of Alligation: 24 - 20 = 4 and 30 - 24 = 6

Ratio = Pen : Pencil = 6 : 4 or 3 : 2

Pen cost: \(\frac{3 }{ 5}\) * 15 = 9

Answer E
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A person purchased a pen and a pencil for 15$. He sold the pen at a 20% profit and the pencil at a 30% profit . if his total profit was 24%, find the cost price of the pen ?
A. 10.50
B. 9.5
C. 11
D. 10
E. 9
Solution:

Let’s let x = the cost of the pen and so (15 - x) = the cost of the pencil. The total price that he sold the pen for, which includes the profit, was 1.2x, and the total price that he sold the pencil for, including profit, was 1.3(15 - x). The total profit on the original $15 cost was 24%, so he sold the pair of items for 1.24 x 15. We can set up the equation:

1.2x + 1.3 (15 - x) = 1.24 x 15

1.2x + 19.5 - 1.3x = 18.60

0.9 = 0.1x

9 = x

The original cost of the pen was $9.

Answer: E
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This is a weighted average problem. Since 24% is closer to 20%, the pen costs more than the pencil (more heavily weighted).

Answer is 9.
Attachments

weightedaverage.png
weightedaverage.png [ 3 KiB | Viewed 7377 times ]

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Can use a Weighted Average Concept to solve the Cost Price of the Pen:

Data Point 1 - 30% Profit on Pencil

Weight of 1 - $Cost Price of Pencil = b


Data Point 2 - 20% Profit on Pen

Weight of 1 - $Cost Price of Pen = a


a + b = $15


the 24% NET Profit is closer to the 20% Profit on the PEN

Using the See-Saw scale

Pencil 30% --------------------------------24% Net Profit --------------------Pen 20%

Total Distance = 30% - 20% = 10

Relative Weighting of Pen = 30% - 24$ = 6

(6/10) of the Total Cost Price of (a + b = $15) is attributable to the Pen


(6/10) * $15 = Cost Price of Pen = $9

-E-
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