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03 Jan 2021, 11:19
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
50% (02:24) correct
50%
(02:27)
wrong
based on 181
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From 1994 to 1995, the revenue of a company increased by x percent. From 1995 to 1996, the revenue decreased by y percent. Is the revenue in 1996 greater than that in 1994?
(1) y < 9 < 10 < x
(2) 5 < y < x < 15
(1) y < 9 < 10 < x
(2) 5 < y < x < 15
04 Jan 2021, 10:30
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From 1994 to 1995, the Percentage Increase is \(x\)
From 1995 to 1996, the percentage Decrease is \(y\)
1. \(y < 9 < 10 < x\)
The value of \(x\) could be \(1\)% to \(10\)%, and y could be \(1\)% to \(8\)% .
Case 1: \(x=10\)% \(y=1\)%
\(1.1*0.99=1.089\) Increase
Case 2: \(x=10\)% \(y=8\)%
\(1.1*0.92=1.012\) Increase
Case 3: \(x=1\)% \(y=8\)%
\(1.01*.92=0.9292\) Decrease
Case 4: \(x=1\)% \(y=1\)%
\(1.01*0.99=0.9999\) Decrease
Insufficient
2. \(5 < y < x < 15\)
\(x= (15+)\)% ; \(y=(1-5)\)%
Let's start with the least case;
\(1.15*0.95=1.0925\)
In other values, the percentage will be increased in the year 1996.
Therefore, Sufficient.
IMO Ans B
From 1995 to 1996, the percentage Decrease is \(y\)
1. \(y < 9 < 10 < x\)
The value of \(x\) could be \(1\)% to \(10\)%, and y could be \(1\)% to \(8\)% .
Case 1: \(x=10\)% \(y=1\)%
\(1.1*0.99=1.089\) Increase
Case 2: \(x=10\)% \(y=8\)%
\(1.1*0.92=1.012\) Increase
Case 3: \(x=1\)% \(y=8\)%
\(1.01*.92=0.9292\) Decrease
Case 4: \(x=1\)% \(y=1\)%
\(1.01*0.99=0.9999\) Decrease
Insufficient
2. \(5 < y < x < 15\)
\(x= (15+)\)% ; \(y=(1-5)\)%
Let's start with the least case;
\(1.15*0.95=1.0925\)
In other values, the percentage will be increased in the year 1996.
Therefore, Sufficient.
IMO Ans B
05 Jan 2021, 09:05
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I'm confused as to how you determined that x could be any value from 1 to 10. The prompt tells us that x is strictly greater than 10 and that y is strictly less than 9.
