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09 Jan 2021, 01:18
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
70% (02:42) correct
30%
(03:17)
wrong
based on 237
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The cost of sending a package is T cents for the first 1/4 kilogram and T/5 cents for each additional 1/4 kilogram or fraction thereof. What is the cost, in cents, to send a P kilogram package at this rate, where P is an integer greater than 1.
A. \(\frac{PT}{20}\)
B. \(\frac{PT-1}{20}\)
C. \((\frac{P}{4}+1)T\)
D. \(\frac{(16P-1)T}{20}\)
E. \(\frac{4(P+1)T}{5}\)
A. \(\frac{PT}{20}\)
B. \(\frac{PT-1}{20}\)
C. \((\frac{P}{4}+1)T\)
D. \(\frac{(16P-1)T}{20}\)
E. \(\frac{4(P+1)T}{5}\)
09 Jan 2021, 02:09
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Bunuel
for simplicity, let's say price of delivery is 4T/5 for every kilogram of delivery.
the cost is
T + \(\frac{4T}{5}\)*\(\frac{P-1}{4}\) =
= T + \(\frac{4T}{5}\)*\(\frac{(4P - 1)}{4}\) =
= T + \(\frac{(4P-1)*T}{5}\)
= T*(\(\frac{(4P-1)}{5}\) + 1)
= T*(\(\frac{(4P+4)}{5}\))
= 4T*(\(\frac{(P+1)}{5}\))
= \(\frac{4(P+1)T}{5}\)
The answer is E
09 Jan 2021, 03:41
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SOLUTION:
Number of quarter kilograms in P kg=4P,
Thus,the cost of sending a P kilogram package is:
T + (T/5)(4P - 1) = 5T/5 + (4PT - T)/5
= (4PT + 4T)/5 = 4T(P + 1)/5 OPTION(E)
Hope this helps
Devmitra Sen(Math)
Number of quarter kilograms in P kg=4P,
Thus,the cost of sending a P kilogram package is:
T + (T/5)(4P - 1) = 5T/5 + (4PT - T)/5
= (4PT + 4T)/5 = 4T(P + 1)/5 OPTION(E)
Hope this helps
Devmitra Sen(Math)
