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Bunuel
If Sam has 5 more marbles than Jack, Jack has 4 more marbles than Frank, and Frank has 5 more marbles than Ted, what is the least number of marbles that must change hands if the four boys are to have an equal number of marbles?

A. 7
B. 8
C. 9
D. 14
E. 28

Ted has the least number of marbles. Frank has 5 more than Ted. Jack has 4 more than Frank i.e. 9 more than Ted.
Sam has 5 more than Jack i.e. 14 more than Ted.

So extra marbles = 5 + 9 + 14 = 28

These need to be divided equally among the four boys so each should get 7.
So Ted will get 7 and Frank will get 2. Total 9 marbles will need to change hands.

Answer (C)
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­Let S= No. marbles Sam, J = no. marbles Jack etc..

Since
S=J+5
J=F+4
F=T+5
T=F-5

Choosing some numbers let S=20 J=15 F=11 T=6

Two marbles can be taken from J to add to F to make them both = 13
Seven marbles can be taken from S and given to T to make them both = 13

2+7=9
IMO C­
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