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08 Mar 2021, 04:15
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84% (01:55) correct
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A mixture contains milk and water in the ratio of 4:3 respectively. If 6 L of water is added to this mixture, the respective ratio of milk and water becomes 8:7. What is the quantity of milk in the original mixture?
(A) 96 L
(B) 48 L
(C) 40 L
(D) 35 L
(E) 30 L
(A) 96 L
(B) 48 L
(C) 40 L
(D) 35 L
(E) 30 L
14 Mar 2021, 03:33
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4x + 3x = 7x
4x/(3x + 6) = 8/7
4x = 48 ----> x = 12
4 * 12 = 48L of Milk and 36 of Water in original mixture
4x/(3x + 6) = 8/7
4x = 48 ----> x = 12
4 * 12 = 48L of Milk and 36 of Water in original mixture
14 Mar 2021, 22:07
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Given that ratio of Milk / Water is 4/3
We can assume original qty as 4x/3x ------(1)
Now it is given that post addition of 6 L water new ratio will become 8/7
Hence
=4x/(3x+6)=8/7
on solving this equation we get x=12
hence from Equation 1 we can get original qty of milk as 4*12=48 L
We can assume original qty as 4x/3x ------(1)
Now it is given that post addition of 6 L water new ratio will become 8/7
Hence
=4x/(3x+6)=8/7
on solving this equation we get x=12
hence from Equation 1 we can get original qty of milk as 4*12=48 L
