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Bunuel
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In the biology lab of "Jefferson" High School there are 5.4*10^6 germs 14 Apr 2021, 14:15
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C
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84% (01:01) correct 16% (01:08) wrong based on 38 sessions

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In the biology lab of "Jefferson" High School there are 5.4*10^6 germs, equally divided among 10,800 Petri dishes. How many germs live happily in a single dish?

A. 100
B. 200
C. 500
D. 1000
E. 5000
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C
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In the biology lab of "Jefferson" High School there are 5.4*10^6 germs 14 Apr 2021, 14:40
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Bunuel
In the biology lab of "Jefferson" High School there are 5.4*10^6 germs, equally divided among 10,800 Petri dishes. How many germs live happily in a single dish?

A. 100
B. 200
C. 500
D. 1000
E. 5000
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No of germs in a single dish = 5.4 * 10^6/10800
54 *10^5/108* 10^2
1*10^3/2
0.5* 10^3
500



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In the biology lab of "Jefferson" High School there are 5.4*10^6 germs 15 Apr 2021, 01:15
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5.4*10^6 germs equally divided among 10,800 Petri dishes = (540*10000)/(108*100)=5*100=500 per dish

opt C
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In the biology lab of "Jefferson" High School there are 5.4*10^6 germs 15 Apr 2021, 02:50
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5.4*10^6
=54000*10^2

=(54000*100)/10800

=500

Answer option C
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In the biology lab of "Jefferson" High School there are 5.4*10^6 germs 22 Apr 2021, 09:30
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Bunuel
In the biology lab of "Jefferson" High School there are 5.4*10^6 germs, equally divided among 10,800 Petri dishes. How many germs live happily in a single dish?

A. 100
B. 200
C. 500
D. 1000
E. 5000
Show more

[header2]Official Explanation[/header3]

The number of germs in a single dish equals the number of germs divided by the number of dishes. The top of the fraction is given in scientific notation. Changing the bottom to scientific notation will allow you to reduce some annoying 0's and work with more comfortable numbers.

Remember the rule: Maintain the balance between the digit term and the exponential term. If one goes up (↑) by a magnitude of 10, the other must go down (↓) by the same magnitude, and vice versa.

Germs: \(5.4×10^6=54×10^5\)

Dishes: \(10,800=108×10^2\)

Germs per dish: \(\frac{54×10^5}{108×10^2}\)

Note that 54108 can be reduced to \(\frac{1}{2}\). Thus, the calculation can be reduced to

\(\frac{1}{2}×\frac{10^5}{10^2}=\frac{1}{2}×10^{5−2}=\frac{1}{2}×10^3\)

\(=\frac{10^3}{2}=\frac{1,000}{2}=500\) germs per dish.

Answer: C
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