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Bunuel
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MarmikUpadhyay
Bunuel
Every matchbox manufactured by a certain factory contains no more than 20% that are defective. What is the minimum number of intact matches in a 43-stick matchbox manufactured by that factory?

A. 39
B. 35
C. 34
D. 33
E. 22

Given: Maximum 20% of the matchsticks are defective.
Minimum number of intact matches in 43-stick matchbox =?


Maximum 20% are defective
=> 20% of 43 = \(\frac{20}{100}\) * 43 = 8.6
=> Maximum of 8 matchsticks can be defective.
=> Minimum number of intact matches = 43 - 8 = 35 matches.

So, correct answer is option B.


why are we considering 8 and not 9?
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AnkithaSrinivas
MarmikUpadhyay
Bunuel
Every matchbox manufactured by a certain factory contains no more than 20% that are defective. What is the minimum number of intact matches in a 43-stick matchbox manufactured by that factory?

A. 39
B. 35
C. 34
D. 33
E. 22

Given: Maximum 20% of the matchsticks are defective.
Minimum number of intact matches in 43-stick matchbox =?


Maximum 20% are defective
=> 20% of 43 = \(\frac{20}{100}\) * 43 = 8.6
=> Maximum of 8 matchsticks can be defective.
=> Minimum number of intact matches = 43 - 8 = 35 matches.

So, correct answer is option B.


why are we considering 8 and not 9?

We are given that maximum 20% of matchsticks i.e. 8.6 are defective. Which means that defective matchsticks cannot be more than 8.6. So we cannot take 9 and can take 8 only.
Hope it helps!
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