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Bunuel
When a two digit number is divided by the sum of its digits, the quotient is 4. If the digits are reversed, the new number is 6 less than twice the original number.
The number is

(A) 12
(B) 21
(C) 24
(D) 42
(E) Both (C) and (D)

If anyone wants to solve this algebraically:

Let the digits of two-digit number be x and y respectively.
So, the number is 10x + y.
Sum of digits = x + y.
Given:
\(\frac{10x + y}{x + y} = 4\)
\(10x + y = 4x + 4y\)
\(2x = y\) - eq(1)

If we reverse the digits, number formed = 10y + x
Given: 10y + x = 2(10x + y) - 6
\(8y = 19x - 6\)
Putting y = 2x from eq(1):
\(16x = 19x - 6\)
\(x = 2\), y = 4

So, the number is 24. IMO, (C)!
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Since the quotient of the division is 4, we can say that the two-digit number is divisible by 4.
Answer options B and D can be eliminated along with answer option E.

Consider option A: If the digits of 12 are reversed, the new number is 21 which is actually more than the original number.
Eliminate answer option A.

The correct answer option is D.

In many many Quant questions, getting to the answer is not the same as solving the question fully. We did not have to solve the question mathematically at all. The elimination strategy is a super-potent weapon that any GMAT aspirant should have in his/her armoury.

Hope that helps!
Aravind B T
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Two-digit number = PQ or 10P + Q

Divided by the sum of its digits, the quotient is 4: \(\frac{(10P + Q)}{ P + Q }= 4 \)

=> 10P + Q = 4P + 4Q

=> 6P - 3Q = 0

=> 2P = Q

If the digits are reversed= 10Q + P

The new number is 6 less than twice the original number = 10 Q + P + 6 = 2 (10P + Q)

=> 10 Q + P + 6 = 20 P + 2 Q

=> 20P + P + 6 = 20P + 4 P

=> 21P + 6 = 24 P

=> 6 = 3P

=> P = 2 and hence, Q = 4

Number is 24

Answer C
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