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Bunuel
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Bunuel
In a class of 25 students, every student takes either Spanish, Latin, or French, or two of the three, but no students take all three languages. 9 take Spanish, 7 take Latin and 5 take exactly two languages. What is the number of students who take French ?

A. 10
B. 11
C. 12
D. 13
E. 14

We know that total no of students are 25
And students taking exactly 2 subjects are 5.
So,
Lets say A= students taking exactly 1 subject and
B= students taking exactly 2 subjects =5

Now,Total no of students= 25= A+B

So, A+5= 25 or, A= 20

Also,
No of students taken Latin (L) + No of students taken Spanish (S) + No of students taken French (F) = A + 2*B

Or, 9+7+F= 20+2*5

Hence, F=30-16=14
So.Total no of students taken french = 14
Hence, E

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Hi there,
Is it possible to solve this question with a double matrix method?
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SNot ST
L527
Not L41418
T91625

We can think of French as neither Spanish and nor Latin. As highlighted here in yellow
The only other assumption i made was that both category is all Spanish and Latin. It doesn't matter as we have the sum and the distribution can be anything.
Hope this helps.

PS: I think this was the unique case given the way the values were provided. i usually stick to venn diagram for 3 category situations. But may be this way can work, I am yet to try this on other similar problems.
georgecambridge
Hi there,
Is it possible to solve this question with a double matrix method?
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