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08 Oct 2021, 08:15
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
57% (02:40) correct
43%
(02:30)
wrong
based on 113
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Not Attempted Yet
Let A be (0, 0) and B be (10, 0). A semicircle is constructed with AB as diameter, and C is a point on the circumference such that BC = 8 cm. What are the coordinates of point C?
(A) (10, 8)
(B) (4.4, 5.6)
(C) (2.8, 6.4)
(D) (6.4, 3.6)
(E) (3.6, 4.8)
(A) (10, 8)
(B) (4.4, 5.6)
(C) (2.8, 6.4)
(D) (6.4, 3.6)
(E) (3.6, 4.8)
17 Oct 2021, 04:13
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Bunuel
We know that the distance between two points whose coordinates are \((x_1,y_1)\) and \((x_2, y_2)\) is given by
\(\sqrt{(x_2-x_1)^2 + (y_2 -y_1)^2}\)..... \((i)\)
We already know \((x_1,y_1)= (10,0) \)
Used the options to find the other point .
if \((x_2, y_2)= (3.6,4.8) \)
\(\sqrt{(3.6 -10)^2 + (4.8 -0)^2}\) ..... using \((i)\)
Then \(\sqrt{(-6.4)^2 + (4.8)^2}\)
\(\sqrt{40.96+ 23.04)} = \sqrt{64} = 8 \)
Only E gives the required distance.
Ans-E
Hope it's clear.
17 Oct 2021, 11:43
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I used a different approach to solve the equation. I created the midpoint D and the possible distance of CD is gonna be 5 (radius = 5) and created one equation and another with the distance of BC. But It seems to be quite a lengthy approach. Does any one have any better suggestion?
