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PyjamaScientist
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Joined: 25 Oct 2020
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Updated on: 25 Oct 2021, 09:20
Originally posted by PyjamaScientist on 25 Oct 2021, 07:42.
Last edited by PyjamaScientist on 25 Oct 2021, 09:20, edited 1 time in total.
Last edited by PyjamaScientist on 25 Oct 2021, 09:20, edited 1 time in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
61% (02:36) correct
39%
(02:51)
wrong
based on 179
sessions
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What is the sum of all values of 'x' that satisfies the equation:
\(\sqrt{6x} = 1 + \sqrt{5x + 3}\)
(A) -28
(B) 20
(C) 0
(D) 28
(E) 38
\(\sqrt{6x} = 1 + \sqrt{5x + 3}\)
(A) -28
(B) 20
(C) 0
(D) 28
(E) 38
25 Oct 2021, 08:45
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PyjamaScientist
\(\sqrt{6x} = 1 + \sqrt{5x + 3}\)
\(\sqrt{6x} -1 =\sqrt{5x + 3}\)
Square both sides
\(6x+1-2\sqrt{6x}=5x+3\)
\(x-2=2\sqrt{6x}\)
Square both sides
\(4+x^2-4x=24x………..x^2-28x-4=0\)
In a quadratic equation \(ax^2+bx+c=0\), the sum of roots =\(\frac{-b}{a}\)
Hence, sum of roots or possible values of x = \(\frac{-(-28)}{1}=28\)
D
30 Mar 2025, 05:18
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Hi that reply helped a lot, especially the trick of -b/a is sum of solutions. Is there a trick for when the product of values that satisfy the equation is asked?
chetan2u
