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23 Nov 2021, 03:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
58% (01:38) correct
42%
(02:19)
wrong
based on 347
sessions
History
Date
Time
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Not Attempted Yet
The value of A varies directly with the square of B and inversely with the cube of C. If C is increased by 300 percent, by what percentage should the value of B increase so that there is no effect on the value of A?
A. 300
B. 400
C. 600
D. 700
E. 800
A. 300
B. 400
C. 600
D. 700
E. 800
13 Dec 2021, 22:24
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As per the question.
C will be (1+300%) which is equal to 4. Hence value of C becomes 4C
A's value will be inversely proportional to cube of C hence its 64C3
In order to get 64 with B we need it to increase by 700% as its square.
B = (1+700%) = 8B
Squaring we get 64B
Now we have neutralised the effect of 64.
Hence D
C will be (1+300%) which is equal to 4. Hence value of C becomes 4C
A's value will be inversely proportional to cube of C hence its 64C3
In order to get 64 with B we need it to increase by 700% as its square.
B = (1+700%) = 8B
Squaring we get 64B
Now we have neutralised the effect of 64.
Hence D
16 Dec 2021, 14:39
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A=kB²/C³
Now A=k(xB)²/(4C)³
Solving, x=8
=> B changes into 8B
%age increase to keep value of A same is given by 8B=B+(y/100)B
y=700
Now A=k(xB)²/(4C)³
Solving, x=8
=> B changes into 8B
%age increase to keep value of A same is given by 8B=B+(y/100)B
y=700
