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Bunuel
If the population of a city increases by \(\frac{100}{9}\%\) per year and if in 2013, the population of the city is 10530 then find the difference between the population of the city in 2015 and 2014.

A. 1300
B. 1400
C. 1700
D. 1800
E. 2000

Breaking Down the Info:

Note this is an exponential population increase, which means the increase per year itself will be increased by \(\frac{100}{9}\% = \frac{1}{9}\) per year.

The current increase from 2013 to 2014 would be \(10530* \frac{1}{9} = (10800 - 270)*\frac{1}{9} = 1200 - 30 = 1170\).

The increase from 2014 to 2015 would be \(\frac{1}{9}\) more. Hence, the increase from 2014 to 2015 is \(1170 * \frac{10}{9} = 130*10 = 1300\).

Answer: A
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