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Bunuel
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Let speed of fastest runner be 3x and speed of slowest runner be x.

If they meet first time at 4m

12x = 4x + 400

8x = 400

x = 400/8

Speed of fastest runner will be

3x 400/8

1200/8

Therefore time it will take for fastest runner to complete race.

3600 /1200/8

24 mins.

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Let the speed of the slowest runner be y.

Speed of fastest runner will then be 3y.

Both meet the first time after 4 minutes.

400+x/3y = 4

12y = 400 + x

Second equation.

x/y = 4

x = 4y

Substituting x in first equations gives

12y = 400 + 4y

12y - 4y = 400

8y = 400

y = 50

So speed of fastest runner

3x50 = 150

Therefore time taken for fastest runner to finish race

3600/150

= 24 minutes.

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Time of meet= Length of the track/relative speed

From the problem; (400/2x)=4. (Assuming the slowest runner speed is X; fastest runner speed is 3X; so relative speed is 2X)

X=50

Then fastest runner run 150m/minute

Inorder to complete the trace fastest runner need 3600/150=24minute

Answer: B
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D1/3x = D2/x = 240
D1 = 720x
D2 = 240x

Now we also know the gap between them is length of the track as they meet for first time.

480x = 400
x=5/6
3x = 5/2

Time taken by Faster:
3600/(5/2) = 1440 seconds = 24 mins

Answer: Option B
Bunuel
In a 3600 m race around a circular track of length 400m, the faster runner and the slowest runner meet at the end of the fourth minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. If the faster runner runs at thrice the speed of the slowest runner. Find the time taken by the faster runner to finish the race.

A. 36 minute
B. 24 minute
C. 16 minute
D. 12 minute
E. 10 minute


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