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Bunuel
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DZ3
Since we include 10 and 100, there are 5 even numbers for every 10 counted (Starting at 10, 12, 14, 16, 18) therefore we have 45 even numbers.

We have 13 multiples of 7 between 10 and 100 of which 7 are even (every second multiple).

\(45-7=38\)

IMO B


Nice approach also but you forget to include the 100. Thus you only get 45 and not 46. Correct answer would be 46-7=39
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Count even numbers from 10 to 100: (100 - 10) / 2 + 1 = 46.

Count even multiples of 7: These are multiples of 14, i.e., 14, 28, 42, 56, 70, 84, 98 — 7 numbers.

Subtract: 46 - 7 = 39.

Answer: C (39)
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