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If a, b and x are integers such that \(a^6=b^3=\frac{|x|}{x}\)
b= 1 and a = 1 or -1

Stat1: \(a^3*b^7>0\); it means a =1, we can get (a- b) now. Sufficient

Stat2: \(a+b>0\); it means a = 1, we can get (a- b) now. Sufficient

So, I think D. :)
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Bunuel
If a, b and x are integers such that \(a^6=b^3=\frac{|x|}{x}\), what is the value of a-b ?

(1) \(a^3*b^7>0\)

(2) \(a+b>0\)

\(a^6=b^3=\frac{|x|}{x}\)

Inference: \(\frac{|x| }{ x}\) can either be 1 or -1. Its given that \(\frac{|x| }{ x}\) = \(a^6\), hence the value of \(\frac{|x|}{x}\) cannot be negative. Thus \(\frac{|x| }{ x}\) = 1.

With that pre-thinking, let see if we can infer anything further

\(a^6 = 1\); so 'a' can be +1 or -1.

\(b^3\) = 1; therefore 'b' = 1


Question

a-b = ?

We already know the value of a, hence if we can know the value (rather positive negative nature) of a, we can answer the question.

Statement 1

\(a^3*b^7>0\)

We already know b = 1, so if \(a^3*b^7>0\) then a is positive. Hence a = 1.

The statement is sufficient to answer, hence we can eliminate B, C and E.

Statement 1

\(a+b>0\)

As b = 1, a cannot be -1 otherwise the sum will be 0 and not greater than 0. So a = 1.

This statement is also sufficient.

Option D
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