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SUPPOSE: Train A at Station A _________meeting point__________Train B at Station B

speed(A) = 50
speed(B) = 60
let distance travelled by A be 'd'
d(A) = d
thus, d(B)= d+100
T = dist/speed
t(A) = \(\frac{d}{50}\)
t(B)=\(\frac{d + 100}{60} \)

since the trains are meeting at point from opposite directions they have travelled for the same time.
thus,\(\frac{d}{50}\) = \(\frac{d + 100}{60} \)
d = d(A) = 500
d(B) = d+100=600
thus, total d=1100'
ANSWER (C)
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