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AnujL
gmatophobia

stuck with this approach

AnujL

11:29, huh? I’m going out on a limb that once we add 24 liters to B, the volume of B is a multiple of 40.

Could it be 40? If it were, that would mean that we started with 16 liters in B and at least 24 liters in A. But the starting amounts are equal, so this doesn’t work.

Could it be 80? If it were, that would mean that we started with 56 liters in B (and therefore 56 liters in each). Hmm, see if you can make your ratio math work from here…(hint: you can!).

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help with this one
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chetan2u
help with this one

AnujL

Did you try it with 56 liters of each, as I suggested?!?

Start
A: 14 water, 42 alcohol
B: 16 water, 40 alcohol
C: 24 water, 32 alcohol

Move 14 from B to C, so 4 water and 10 alcohol.

C: 28 water, 42 alcohol

28:42 = 2:3

Answer choice A.

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Suraj0184
Three solutions A, B and C having equal volume are made up of water and alcohol in the ratio 1:3, 2:5 and 3:4 respectively. 24 litres of A is taken out and mixed into B, then the composition of water and alcohol in B changes to 11:29. Had 14 litres been taken from the original B solution and mixed into C, what would had been the final ratio of C?

A. 2:3
B. 3:4
C. 4:5
D. 5:6
E. 6:7

(Source : Wizako)

24 litres of A 1:3 means 6:18 is mixed in B 2:5.
Finding y and z
Thus, 6+2y=11z and 18+5y=29z
Or 30+10y=55z and 36+10y=58z
Thus, 6=3z or z=2 and 6+2y=11*2 or y=8

Total volume of each
(2+5)*8=56

14 litres of B2:5 means 4:10 is mixed into 3:4 of C. 3:4 of C, total of 56, means 24:32.
Thus final ratio = 4+24 : 10+32 = 28:42 = 2:3

A
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