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Bunuel
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sumit99kr
S1) xy + y is odd i.e, y(x+1) is odd. Product of two quantities is odd only when both are odd.
'y' is odd and (x+1) is odd.
If (x+1) is odd then x is even.
Hence S1 is sufficient.

S2) y is odd, we cannot conclude anything about x, hence not sufficient.

Hence I would go with A.

Posted from my mobile device
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Bunuel
If x and y are integers, is x odd?

(1) xy + y is odd
(2) y is odd

Statement One Alone:

\(\Rightarrow\) xy + y is odd

Remember that if a number is odd, then all of its factors must also be odd. If we factor y out of xy + y, we obtain y(x + 1). Since y(x + 1) is odd, both y and x + 1 must be odd, which means x is even. Thus, the answer to the question is no. Statement one alone is suffcient.

Eliminate answer choices B, C, and E.

Statement Two Alone:

\(\Rightarrow\) y is odd

Without any information about x, we cannot determine whether x is even or odd. Statement two alone is not suffcient.

Answer: A
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Bunuel
If x and y are integers, is x odd?

(1) xy + y is odd
(2) y is odd

Statement 1

xy + y = odd

Case 1: y is odd

xy = odd - odd = even

We know y is odd, so x = even

Case 2: y is even

xy = odd - even = odd

This is not possible, as y is even so the product of two integers has to be even. We will discard case 2.

The statement is sufficient.

Statement 2

y is odd

Insufficient.

Option A
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