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09 Feb 2023, 12:50
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B
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Difficulty:
25%
(medium)
Question Stats:
80% (01:54) correct
20%
(02:24)
wrong
based on 159
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The sum of sixty numbers in an arithmetic progression is 7800. If the largest of the numbers is 12 times the smallest, what is the value of the smallest number?
A. 25
B. 20
C. 15
D. 12
E. 10
A. 25
B. 20
C. 15
D. 12
E. 10
09 Feb 2023, 23:15
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The sum of sixty numbers in an arithmetic progression is 7800. If the largest of the numbers is 12 times the smallest, what is the value of the smallest number?
Let the smallest number be m, and the largest number be 12m.
Using the formula, Sum of A.P = \(\frac{(first term + last term)}{2}\) x No. of terms in A.P
or, 7800 = \(\frac{(m + 12m)}{2}\) x 60
or, 7800 = 13m x 30
Dividing both sides by 30 and 13, we get m=20
Therefore, choice B is correct.
Let the smallest number be m, and the largest number be 12m.
Using the formula, Sum of A.P = \(\frac{(first term + last term)}{2}\) x No. of terms in A.P
or, 7800 = \(\frac{(m + 12m)}{2}\) x 60
or, 7800 = 13m x 30
Dividing both sides by 30 and 13, we get m=20
Therefore, choice B is correct.
13 Nov 2025, 08:03
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