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Akriti_Khetawat
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Bunuel
If a is a positive integer, which of the following is equal to \((-4^a)^{-4} + (-2^4)^{-2a}\) ?

A. \(-2^{-8a + 1}\)

B. \(-2^{-16a + 1}\)

C. \(2\)

D. \(2^{-8a + 1}\)

E. \(2^{-16a + 1}\)

\((-4^a)^{-4} + (-2^4)^{-2a}\)

\((-1)^{-4}(4^a)^{-4} + (-1)^{-2a}(2^4)^{-2a}\)

\((2^{2a})^{-4} + (2^4)^{-2a}\)

\(2* 2^{-8a}\)

\(2^{-8a + 1}\)

Option D
Hi what happens to the -1 in this solution? Do they get cancelled?

When raised to any nonzero even power, (-1) becomes 1. So, \( (-1)^{-4}=1 \) and \( (-1)^{-2a} =1\). Since these terms evaluate to 1, they are simply dropped from the equation.
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Akriti_Khetawat
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Bunuel
If a is a positive integer, which of the following is equal to \((-4^a)^{-4} + (-2^4)^{-2a}\) ?

A. \(-2^{-8a + 1}\)

B. \(-2^{-16a + 1}\)

C. \(2\)

D. \(2^{-8a + 1}\)

E. \(2^{-16a + 1}\)

\((-4^a)^{-4} + (-2^4)^{-2a}\)

\((-1)^{-4}(4^a)^{-4} + (-1)^{-2a}(2^4)^{-2a}\)

\((2^{2a})^{-4} + (2^4)^{-2a}\)

\(2* 2^{-8a}\)

\(2^{-8a + 1}\)

Option D
Hi what happens to the -1 in this solution? Do they get cancelled?


I think what happens is that (-1)^2n [ -1 RAISED TO ANY EVEN NUMBER] will always be positive so they become +1 which is where they disappear after multiplication
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