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satyaprakash89
D (N,N) = 1/2 * 49/99 = 49/198 Probability of at least one ticket to win = 1 -(N,N) = 1 -49/198 =149/198 . Why it cannot be D?
It seems you made a misinterpretation that 50 tickets win and 50 lose, the question says that each of the 100 tickets has a 50% chance of win or lose, so when you randomly draw two tickets, each of the two has a 1/2, 1/2 chance of losing. Therefore, chance of losing = 1/2 * 1/2 = 1/4, and chance of at least one winning = 3/4.
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