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14 Dec 2023, 01:07
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Dropdown 1: 126
Dropdown 2: 1.45
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
40% (03:19) correct
60%
(03:37)
wrong
based on 239
sessions
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Not Attempted Yet
Data Insights (DI) Butler 2023-24 [Question #151, Date: Dec-11-2023] [Click here for Details]
The graph shows a family’s monthly electricity consumption, in kWh, over the course of two years.
Based on the given information, fill in the blanks in each of the following statements.
1. The family’s electricity consumption in January 2011 was approximately % of its consumption in December 2010.
2. If the family paid a constant rate of $x per kWh between June 2010 and November 2010, inclusive, then it paid as much between June 2010 and August 2010, inclusive, as it did between September 2010 and November 2010, inclusive.
Attachment:
1.jpg [ 51.67 KiB | Viewed 3893 times ]
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Graphs and Tables (G&T) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
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ShowHide Answer
Official Answer
Dropdown 1: 126
Dropdown 2: 1.45
14 Dec 2023, 08:00
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Statement 1 :
The family’s electricity consumption in January 2011 was approximately ___ % of its consumption in December 2010.
=>
Electricity consumption in (Jan 2011 / Dec 2010) x 100 %
Approximation - (29/22.5) x 100
= 126%
Statement 2 :If the family paid a constant rate of $x per kWh between June 2010 and November 2010, inclusive, then it paid ____ as much between June 2010 and August 2010, inclusive, as it did between September 2010 and November 2010, inclusive.
=>
Electricity consumption in the months of (June 2010 + July 2010 + Aug 2010) / (Sep 2010 + Oct 2010 + Nov 2010)
Approximation - ( 70 / 47 )
= 1.45 times
The family’s electricity consumption in January 2011 was approximately ___ % of its consumption in December 2010.
=>
Electricity consumption in (Jan 2011 / Dec 2010) x 100 %
Approximation - (29/22.5) x 100
= 126%
Statement 2 :If the family paid a constant rate of $x per kWh between June 2010 and November 2010, inclusive, then it paid ____ as much between June 2010 and August 2010, inclusive, as it did between September 2010 and November 2010, inclusive.
=>
Electricity consumption in the months of (June 2010 + July 2010 + Aug 2010) / (Sep 2010 + Oct 2010 + Nov 2010)
Approximation - ( 70 / 47 )
= 1.45 times
01 Jun 2024, 10:52
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I dont understand the options for statement 2. Is there supposed to be a difference between 1.45 and 1.45x?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Graphs and Tables (G&T) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
