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26 Dec 2023, 02:30
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Difficulty:
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Question Stats:
66% (01:36) correct
34%
(01:56)
wrong
based on 308
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If \(y=-x^2+6x+5\), then what is the greatest possible value of y ?
(A) 5
(B) 12
(C) 13
(D) 14
(E) 15
(A) 5
(B) 12
(C) 13
(D) 14
(E) 15
07 Nov 2024, 01:10
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The maximum value for any quadratic equation occurs at -b/2a
Hence, put X= -b/2a = -6/-2= 3
Value of Y at X=3 is 14
Hence, put X= -b/2a = -6/-2= 3
Value of Y at X=3 is 14
General Discussion
26 Dec 2023, 02:40
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If we take the first derivative of the equation to find the maximum we will have
f'(x) = -2x + 6 = 0
Then x = -6/-2 = 3
When x=3 -> f(3) = -3^2 + 6(3) + 5 = 14
This is the max value
Answer D
Correct me if I'm wrong anywhere
Posted from my mobile device
f'(x) = -2x + 6 = 0
Then x = -6/-2 = 3
When x=3 -> f(3) = -3^2 + 6(3) + 5 = 14
This is the max value
Answer D
Correct me if I'm wrong anywhere
Posted from my mobile device
