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29 Dec 2023, 12:10
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Dropdown 1: 9
Dropdown 2: City Y
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
27% (02:57) correct
73%
(03:12)
wrong
based on 239
sessions
History
Date
Time
Result
Not Attempted Yet
Data Insights (DI) Butler 2023-24 [Question #177, Date: Dec-29-2023] [Click here for Details]
The graph shows the unemployment rates for three cities between 2000 and 2011. During this period, the total population of City X grew from 1.3 million to 1.7 million; of City Y grew from 2.1 million to 2.3 million; and of City Z decreased from 1.2 million to 1.1 million.
Based on the given information, fill in the blanks in each of the following statements.
The unemployment rate in City X was times greater than the average of the unemployment rates in Cities Y and Z.
Among these three cities in the year 2000, had the greatest number of unemployed people.
Attachment:
1.jpg [ 71.77 KiB | Viewed 4553 times ]
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Official Answer
Dropdown 1: 9
Dropdown 2: City Y
02 Jan 2024, 11:55
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Official Explanation
Don’t waste time trying to calculate exact averages. Rather, think about the different cases in which City X’s unemployment rate would have been greater than the average unemployment rate of the other two cities. One such case is when City X’s rate is greater than either of the other two rates. This happened every year from 2000 to 2005. Next, City X’s unemployment rate will be greater than the average unemployment rate of the other two cities when City X’s rate is between the two other rates, but closer to the larger one of the two. This happened in 2006, 2007, and 2009. In 2011, City X’s rate was between the other two but closer to the lower of the two, while in 2008 and 2010 City X’s rate was the lowest of the three. Thus, in all but these three years (that is, in a total of 9 years), City X’s rate was greater than the average of the other two rates.
The correct answer is (C).
In 2000, City X had the highest unemployment rate, but City Y was significantly more populous. The 4% of City Y’s 2.1 million residents who were unemployed are more than the 5.8% of City X’s 1.3 million residents or the 5.2% of City Z’s 1.2 million residents. Thus, the correct answer is choice (B).
The correct answer is (B).
Don’t waste time trying to calculate exact averages. Rather, think about the different cases in which City X’s unemployment rate would have been greater than the average unemployment rate of the other two cities. One such case is when City X’s rate is greater than either of the other two rates. This happened every year from 2000 to 2005. Next, City X’s unemployment rate will be greater than the average unemployment rate of the other two cities when City X’s rate is between the two other rates, but closer to the larger one of the two. This happened in 2006, 2007, and 2009. In 2011, City X’s rate was between the other two but closer to the lower of the two, while in 2008 and 2010 City X’s rate was the lowest of the three. Thus, in all but these three years (that is, in a total of 9 years), City X’s rate was greater than the average of the other two rates.
The correct answer is (C).
In 2000, City X had the highest unemployment rate, but City Y was significantly more populous. The 4% of City Y’s 2.1 million residents who were unemployed are more than the 5.8% of City X’s 1.3 million residents or the 5.2% of City Z’s 1.2 million residents. Thus, the correct answer is choice (B).
The correct answer is (B).
General Discussion
31 Dec 2023, 06:28
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Is there any short technique via which we can reach to the answer for the first question ? Else crude calculation method will consume a lot of time.
