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10 May 2024, 01:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
84% (01:48) correct
16%
(02:45)
wrong
based on 256
sessions
History
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Time
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If \(\frac{x}{y}=2.5\) and \(x^2 y^3 = 200\), what is the value of \(xy\)?
A. 2
B. 5
C. 6.25
D. 10
E. 32
A. 2
B. 5
C. 6.25
D. 10
E. 32
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01 Jun 2024, 05:00
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Official Solution:
If \(\frac{x}{y}=2.5\) and \(x^2 y^3 = 200\), what is the value of \(xy\)?
A. 2
B. 5
C. 6.25
D. 10
E. 32
Upon cross-multiplying \(\frac{x}{y}=2.5\), we get \(x=2.5y\). Plugging this into \(x^2 y^3 = 200\), we have \((2.5y)^2*y^3=6.25y^5=200\). Simplifying, we get \(y^5=32\), which implies \(y=2\). Then, \(x=2.5y=5\). Therefore, \(xy=10\).
Answer: D
If \(\frac{x}{y}=2.5\) and \(x^2 y^3 = 200\), what is the value of \(xy\)?
A. 2
B. 5
C. 6.25
D. 10
E. 32
Upon cross-multiplying \(\frac{x}{y}=2.5\), we get \(x=2.5y\). Plugging this into \(x^2 y^3 = 200\), we have \((2.5y)^2*y^3=6.25y^5=200\). Simplifying, we get \(y^5=32\), which implies \(y=2\). Then, \(x=2.5y=5\). Therefore, \(xy=10\).
Answer: D
General Discussion
10 May 2024, 01:52
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Bunuel
\(\frac{x}{y}=2.5\)
\(\frac{x}{y}=\frac{5}{2}\)
\(x=\frac{5}{2}*y\)
\(x^2 y^3 = 200\)
\(\frac{25}{4}*y^2 * y^3 = 200\)
\(y^5 = 32\)
\(y = 2\)
Therefore, x = 5
x * y = 10
Option D
