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Fish181
Joined: 13 Dec 2023
Last visit: 10 Aug 2026
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Status:Applying in R1 of 2024 to t15
Affiliations: University of Tennessee
Location: United States (CO)
Concentration: Strategy, Finance
GMAT Focus 1: 605 Q76 V84 DI80 
GMAT Focus 2: 615 Q78 V86 DI78
GPA: 3.62
WE:Analyst (Consumer Packaged Goods)
GMAT Focus 2: 615 Q78 V86 DI78
Posts: 127
26 May 2024, 11:31
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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A farmer determines that the price P per pound of a certain seasonal product and the number S of pounds of this product sold per month are related by the formula \(P = \frac{K}{\sqrt{S}}\) where S > 0 and K is a constant. If S decreases by 75 percent, then by what percent does the price P increase, according to this formula?
A. 150%
B. 100%
C. 75%
D. 50%
E. 25%
GMAT-Club-Forum-mbw7ol2v.png [ 24.2 KiB | Viewed 3351 times ]
A. 150%
B. 100%
C. 75%
D. 50%
E. 25%
[From Mock 5]
Attachment:
GMAT-Club-Forum-mbw7ol2v.png [ 24.2 KiB | Viewed 3351 times ]
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26 May 2024, 13:22
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Fish181
We are given that for some constant K, \(K = P\sqrt{S}\).
If S' becomes S/4, which corresponds to a decrease of 75%, then \(\sqrt{S'}=\sqrt{\frac{S}{4}}=\frac{\sqrt{S}}{2}\). To maintain the same constant K, P' must become 2P, which corresponds to a 100% increase.
Answer: B.
Attachment:
GMAT-Club-Forum-6xgvc7jd.png [ 24.2 KiB | Viewed 3325 times ]
28 May 2024, 02:24
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Q. A farmer determines that the price P per pound of a certain seasonal product and the number S of pounds of this product sold per month are related by the formula P=KS√𝑃=𝐾𝑆 where S > 0 and K is a constant. If S decreases by 75 percent, then by what percent does the price P increase, according to this formula?
Sol: Assumed K as 32 and S as 16 (as it will be easier to calculate)
P= k/√s
= 32/√16
= 32/4
=8
Now let's decrease S by 75%, which will be 16*1/4=4 and keep the K contsant as 32.
P= 32/√4
= 32/2
= 16
So the resulting value of P increased from 8 to 16, an increase of 100%. Ans. choice B.
Sol: Assumed K as 32 and S as 16 (as it will be easier to calculate)
P= k/√s
= 32/√16
= 32/4
=8
Now let's decrease S by 75%, which will be 16*1/4=4 and keep the K contsant as 32.
P= 32/√4
= 32/2
= 16
So the resulting value of P increased from 8 to 16, an increase of 100%. Ans. choice B.
