For every musical tone, f is the frequency, in cycles per second, of

Question

For every musical tone, f is the frequency, in cycles per second, of the musical tone and w is the wavelength, in feet, of the musical tone, then the product fw is a constant. The middle C musical tone has a frequency of 260 cycles per second and wavelength of approximately 4 feet, while a certain G musical tone has a frequency of 390 cycles per second. which of the following is closest to the wavelength, in feet, of the G musical tone?

A. \(2 \frac{2}{3}\)

B. \(4 \frac{2}{3}\)

C. \(5 \frac{1}{2}\)

D. \(6\)

E. \(32 \frac{1}{2}\)

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Source is GMAT Official Practice test 6.

A.  2 \frac{2}{3}

B.  4 \frac{2}{3}

C.  5 \frac{1}{2}

D.  6

E.  32 \frac{1}{2}

Source is GMAT Official Practice test 6.

Purnank · Answer

f*w = Constant.
Therefore,
f1*w1 = f2*w2
f1 = 260, w1 = 4
f2 = 390, w2 = ?
Substitute values you will get 
w2=8/3 = 2 + 2/3
Answer A.

sahilsahh · Answer

260 * 4 = 390 * w₂

1040 = 390 * w₂

w₂ = 1040 / 390

w₂ ≈ 2.67 feet

maink · Answer

the product of f and w will be constant

hence, f1*w1 = f2*w2

substituting values, we get 
260 * 4 = 390 * w2

1040 = 390 * w2

w2 = 1040 / 390

w2 = 2.67 feet

educatdspeculator · Answer

When we see the word  constant  we immediately know:

Middle C tone = Middle G tone

Middle tone = (f)(w)
f = frequency
w = wavelength

Middle C tone = Middle G tone

f1 = frequency Middle C tone = 260
w1 = wavelength Middle C tone = 4
f2 = frequency Middle G tone = 390
w2 = wavelength Middle G tone =  ?

(f1)(w1) = (f2)(w2)

(260)(4) = (390)(w2)
1040 / 390 = w2
~2.67 = w2

Correct Answer is A.

For every musical tone, f is the frequency, in cycles per second, of

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For every musical tone, f is the frequency, in cycles per second, of