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07 Oct 2024, 01:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
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Question Stats:
78% (01:34) correct
22%
(01:46)
wrong
based on 95
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Date
Time
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Not Attempted Yet
A television advertising break is to consist of six 30-second advertisements. If the second, fourth, and sixth of the 30-second spots are to be filled with three different advertisements for company X and the other spots are to be filled with one advertisement each for companies A, B, and C, in how many different ways can the six advertisements be ordered?
(A) 729
(B) 720
(C) 120
(D) 36
(E) 24
(A) 729
(B) 720
(C) 120
(D) 36
(E) 24
07 Oct 2024, 01:48
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Company X can fill advertisement 2/4 and 6 in 3! ways since the advertisements are different
and 1 3 and 5 spots can be filled in 3*2*1 way = 6 ways
so 6*6
Total = 36
D
and 1 3 and 5 spots can be filled in 3*2*1 way = 6 ways
so 6*6
Total = 36
D
07 Oct 2024, 01:53
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3 ads of Company X can be arranged in Spots 2, 4 & 6 in \(3!\) ways
Ads of A, B & C can be arranged in Spots 1, 3, & 5 in \(3!\) ways
Total ways\(=3!*3!=6*6=36\)
Answer: D
Ads of A, B & C can be arranged in Spots 1, 3, & 5 in \(3!\) ways
Total ways\(=3!*3!=6*6=36\)
Answer: D
