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-|-7x+11| & x is an integer
-|-7x+11|=0
-7x+11=0
x=11/7 or for -|-7x+11| to be maximum, x has to be either 1 or 2 (as x is an integer)
If x=1, -|-7+11|= -4
If x=2, -|-7(2)+11|= -3
The maximum of above expression is when x=2; -|-7x+11|= -3

Answer: B
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We need to find the maximum value of -|-7x + 11|

To find the maximum value of a negative number, we need to find the minimum value of the absolute number
=> we need to find the minimum value of |-7x + 11| or minimum value of |11 - 7x|

Now, we know that x is an integer and minimum value of modulus of a number is 0
=> 11 - 7x = 0
=> x = \(\frac{11}{7}\) ~ 1.6

=> Lets try x = 1 and x = 2
=> x = 1, | 11 - 7x | = | 11 - 7 | = | 4 | = 4
=> x = 2, | 11 - 7x | = | 11 - 7*2 | = | 11 - 14 | = | -3 | = 3
=> Minimum value of | 11 - 7x | = 3

-| 11 - 7x | = -3

So, Answer will be B
Hope it helps!

Watch the following video to MASTER Absolute Values

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