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25 Nov 2024, 01:30
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
45% (02:05) correct
55%
(02:17)
wrong
based on 225
sessions
History
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Time
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Not Attempted Yet
A, B and C are assigned the task of making the same type of clay toys. How many clay toys are made in a day when all three work together?
(1) In one day, A, working alone, can make one-fourth as many clay toys as B, working alone, can and three fifth as many clay toys as C, working alone, can
(2) When B works at 50% capacity, B and A can make 65 toys in a day and B and C can make 45 toys in a day
(1) In one day, A, working alone, can make one-fourth as many clay toys as B, working alone, can and three fifth as many clay toys as C, working alone, can
(2) When B works at 50% capacity, B and A can make 65 toys in a day and B and C can make 45 toys in a day
26 Nov 2024, 10:32
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Bunuel
(1) In one day, A, working alone, can make one-fourth as many clay toys as B, working alone, can and three fifth as many clay toys as C, working alone, can
let \(x \) be the # of toys, that \(b\) makes in a day then, total toys in a day:
\( \frac{x}{4} + x + \frac{5x}{12} \)
We do not know \(x\)
INSUFF.
(2) When B works at 50% capacity, B and A can make 65 toys in a day and B and C can make 45 toys in a day
Let \(a\), \(b\) and \(c\) be the number of days that a,b, c take to get the work done.
\( \frac{1}{a} + \frac{1}{2b} = 65\)
\(\frac{1}{2b} + \frac{1}{c} = 45\)
adding both the equations above.
\( \frac{1}{a} + \frac{1}{b} + \frac{1}{c} =110\)
SUFF.
Ans B
Hope it helped.
01 Aug 2025, 23:57
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IMO, the real trap here is for the time. The moment you go into fractions, you are falling for the trap. Because you solve it in 2mins instead of 20seconds. We can go like this
Say, Ra, Rb and Rc are respective rates in units such as work done per some time. Here the units are number of clay toys/day of time.
Question translates to if (Ra+Rb+Rc)(1)=?
1) Given Ra:Rb:Rc. I wont even bother reading ratios. Because, this is clearly insufficient to answer the addition of those above
2) B works at 50% capacity ie Rb/2. Then given Ra+Rb/2=65 and Rb/2+Rc=45. We can add these two to get Ra+Rb+Rc. So sufficient
Say, Ra, Rb and Rc are respective rates in units such as work done per some time. Here the units are number of clay toys/day of time.
Question translates to if (Ra+Rb+Rc)(1)=?
1) Given Ra:Rb:Rc. I wont even bother reading ratios. Because, this is clearly insufficient to answer the addition of those above
2) B works at 50% capacity ie Rb/2. Then given Ra+Rb/2=65 and Rb/2+Rc=45. We can add these two to get Ra+Rb+Rc. So sufficient
