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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Sorry do you mean 8 hours for Ramesh instead of 10? How did you arrive at 10 hours for Ramesh? Thanks
EshaFatim
IMO the answer is B.

Statement 1 is insufficient as no time is mentioned.

Statement 2

Suppose, total distance = d
Prem's total time = 6 hours
Prem's speed = \(\frac{d}{6}\)

Ramesh's total = 10 hours
Ramesh's speed = \(\frac{d}{10}\)

Prem got a headstart and continued for 2 hours until Ramesh started. In those 2 hours Prem crossed -
= \(\frac{d}{6} * 2\)
= \(\frac{d}{3}\) km

Now when Ramesh joined, the relative speed stands \(= \frac{d}{6}+\frac{d}{10} = \frac{16d}{60} = \frac{4d}{15}\)

Relative time = \(\frac{Distance }{ Relative Speed}\\
= \frac{Total Distance - Distance Prem Crossed Before Ramesh Started}{Relative Speed}\\
= (d-d/3) / \frac{4d}{15}\\
= \frac{2d}{3}*\frac{15}{4d}\\
= 2.5 hours\)

Now total time passed when they met, since Prem started
= time taken by Prem before Ramesh started + when they met after Ramesh started
= 2 hours + 2.5 Hours
= 4.5 hours

They'll meet at = 5:00 AM + 4.5 hours = 9:30 AM.

So statement 2 is sufficient.

ANSWER B
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namratajoshi28
Sorry do you mean 8 hours for Ramesh instead of 10? How did you arrive at 10 hours for Ramesh? Thanks

Yes you're right. My bad. Edited accordingly. Thanks!
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