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27 Nov 2024, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
76% (02:28) correct
24%
(02:33)
wrong
based on 379
sessions
History
Date
Time
Result
Not Attempted Yet
XYX
−YXY
ZXW
In the subtraction problem above, X, Y and Z are positive digits and the product of digit X and digit Y is 12. What is the value of X – Y?
A. –4
B. –1
C. 1
D. 3
E. 4
−YXY
ZXW
In the subtraction problem above, X, Y and Z are positive digits and the product of digit X and digit Y is 12. What is the value of X – Y?
A. –4
B. –1
C. 1
D. 3
E. 4
27 Nov 2024, 22:10
Kudos
Bookmarks
Here’s the solution without any markdown formatting:
---
Problem:
X Y X
- Y X Y
-------
Z X W
In the subtraction problem above, X, Y, and Z are positive digits, and the product of digit X and digit Y is 12. What is the value of X – Y?
Options:
A. –4
B. –1
C. 1
D. 3
E. 4
Solution:
We are given the subtraction problem:
X Y X
- Y X Y
-------
Z X W
With the following conditions:
1. X, Y, and Z are positive digits.
2. X × Y = 12.
Step 1: Determine Possible Values for X and Y
Since X × Y = 12 and both X and Y are single digits, the possible pairs (X, Y) are:
- (2, 6)
- (3, 4)
- (4, 3)
- (6, 2)
Step 2: Test Each Pair to Satisfy the Subtraction
Let's evaluate each possible pair to see which one makes the subtraction valid.
Option 1: X = 2, Y = 6
2 6 2
- 6 2 6
-------
- Hundreds Place: 2 - 6 is invalid without borrowing.
Conclusion: This pair doesn't work.
Option 2: X = 3, Y = 4
3 4 3
- 4 3 4
-------
- Hundreds Place: 3 - 4 is invalid without borrowing.
Conclusion: This pair doesn't work.
Option 3: X = 4, Y = 3
4 3 4
- 3 4 3
-------
- Units Place: 4 - 3 = 1 → W = 1
- Tens Place: 3 - 4 requires borrowing. After borrowing:
- Tens digit becomes 13 - 4 = 9 → X = 9
- Hundreds Place: After borrowing, 3 - 3 = 0. However, Z must be a positive digit.
Conclusion: This pair doesn't work.
Option 4: X = 6, Y = 2
6 2 6
- 2 6 2
-------
- Units Place: 6 - 2 = 4 → W = 4
- Tens Place: 2 - 6 requires borrowing. After borrowing:
- Tens digit becomes 12 - 6 = 6 → X = 6
- Hundreds Place: After borrowing, 5 - 2 = 3 → Z = 3
The subtraction is valid with Z = 3, X = 6, and W = 4.
Conclusion: This pair works.
Final Calculation:
Given X = 6 and Y = 2,
X - Y = 6 - 2 = 4
Answer:
4 (Option E)
---
Problem:
X Y X
- Y X Y
-------
Z X W
In the subtraction problem above, X, Y, and Z are positive digits, and the product of digit X and digit Y is 12. What is the value of X – Y?
Options:
A. –4
B. –1
C. 1
D. 3
E. 4
Solution:
We are given the subtraction problem:
X Y X
- Y X Y
-------
Z X W
With the following conditions:
1. X, Y, and Z are positive digits.
2. X × Y = 12.
Step 1: Determine Possible Values for X and Y
Since X × Y = 12 and both X and Y are single digits, the possible pairs (X, Y) are:
- (2, 6)
- (3, 4)
- (4, 3)
- (6, 2)
Step 2: Test Each Pair to Satisfy the Subtraction
Let's evaluate each possible pair to see which one makes the subtraction valid.
Option 1: X = 2, Y = 6
2 6 2
- 6 2 6
-------
- Hundreds Place: 2 - 6 is invalid without borrowing.
Conclusion: This pair doesn't work.
Option 2: X = 3, Y = 4
3 4 3
- 4 3 4
-------
- Hundreds Place: 3 - 4 is invalid without borrowing.
Conclusion: This pair doesn't work.
Option 3: X = 4, Y = 3
4 3 4
- 3 4 3
-------
- Units Place: 4 - 3 = 1 → W = 1
- Tens Place: 3 - 4 requires borrowing. After borrowing:
- Tens digit becomes 13 - 4 = 9 → X = 9
- Hundreds Place: After borrowing, 3 - 3 = 0. However, Z must be a positive digit.
Conclusion: This pair doesn't work.
Option 4: X = 6, Y = 2
6 2 6
- 2 6 2
-------
- Units Place: 6 - 2 = 4 → W = 4
- Tens Place: 2 - 6 requires borrowing. After borrowing:
- Tens digit becomes 12 - 6 = 6 → X = 6
- Hundreds Place: After borrowing, 5 - 2 = 3 → Z = 3
The subtraction is valid with Z = 3, X = 6, and W = 4.
Conclusion: This pair works.
Final Calculation:
Given X = 6 and Y = 2,
X - Y = 6 - 2 = 4
Answer:
4 (Option E)
17 Dec 2024, 01:47
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XYX
-YXY
ZXW
In the subtraction problem above, X, Y and Z are positive digits and the product of digit X and digit Y is 12. What is the value of X – Y?
A. –4
B. –1
C. 1
D. 3
E. 4
X * Y = 12
Options for X & Y = 3,4,2,6 (Cant be 12 and 1 as 12 becomes 2 digit number)
Note Z is positive hence the number XYX>YXY
So X could be 4 if Y is 3 and X could be 6 if Y is 2 not vice versa given the way the problem is structured.
Lets randomly take any out of 4 and 6 and see how it goes or else we will take another
626
-262
364
6-2 = 4
E
-YXY
ZXW
In the subtraction problem above, X, Y and Z are positive digits and the product of digit X and digit Y is 12. What is the value of X – Y?
A. –4
B. –1
C. 1
D. 3
E. 4
X * Y = 12
Options for X & Y = 3,4,2,6 (Cant be 12 and 1 as 12 becomes 2 digit number)
Note Z is positive hence the number XYX>YXY
So X could be 4 if Y is 3 and X could be 6 if Y is 2 not vice versa given the way the problem is structured.
Lets randomly take any out of 4 and 6 and see how it goes or else we will take another
626
-262
364
6-2 = 4
E
Bunuel
